Proof of Pythagoras Theorem
Quadratic Equation:
ax2 + bx + c = 0
MathPi
Proof of Pythagoras Theorem
Step 1
Draw a right-angled triangle with sides a, b, and c, where c is the hypotenuse (the side opposite the right angle).
Step 3
Draw squares with sides a and b on the other two sides of the triangle. The areas of the squares are a² and b².
Step 4
Remove the triangles from the squares and rearrange the squares as shown in the diagram. The new square has sides a + b and area (a + b)² = a² + b² + 2ab.
Step 5
Equating the area of the new square to the sum of the areas of the smaller squares, we get:
(a + b)² = a² + b² + 2ab
a² + 2ab + b² = a² + b² + c²
2ab = c² - a² - b²





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